Category: Uncategorized

  • For my final project, I sought a dataset related to housing, as I work in property management and felt housing was a good starting point. I settled in using a dataset bult in R, the ‘Boston’ dataset. This dataset has 506 observations and 14 variables: Hypothesis using the Boston dataset: Do homes near the Charles…

  • 1. 2. 3. The time-series plot makes it clear that student credit card charges steadily increased across 2012 and 2013. Even though there are a few small dips month to month, the overall pattern trends upward, especially toward the end of each year. There isn’t a strong seasonal pattern or any big recurring spikes, but…

  • 12.1: R Results 12.3: R Results: 12.1 Comparison of Additive Model and Paired t-Test Results: Both the additive model and paired t-test show a significant treatment effect. In the additive model, the active treatment lowered VAS scores by about –42.9 (p = 0.0056) after adjusting for period and subject. The period effect was also marginally…

  • Analysis For this analysis, I ran a multiple linear regression and ANOVA using the cystfiber dataset to study how age, weight, BMP, and FEV1 affect spemax. The regression model was:spemax = -11.094 – 12.775(age) + 4.319(weight) – 2.833(bmp) + 59.886(fev) The model showed a strong overall fit (R² = 0.7019, p = 0.0106), meaning about…

  • The first ANOVA examined reaction times under high, moderate, and low stress conditions. Results revealed a statistically significant effect of stress level on reaction time, F(2, 15) = XX.XX, p < .001, indicating that greater stress levels correspond to slower reaction responses. The ANOVA results (F = 26.7, p < 0.001) indicate a significant difference…

  • 1.1 : Define the Relationship Model: y is the response variable which is the dependent variable, this is the variable that we are predicting. x is the predictor variable which is the independent variable, this is variable we are using to predict y. y depends linearly on x which follows the equation: Y = a…

  • A. Population Mean = (8+14+16+10+11)/(5) = 59/5 = 11.8 B. Taking a random sample of 2 from 5 members: There are 10 possible members. Sample 1 Values: 8, 14 Sample Mean: 11 Sample 2 Values: 8, 16 Sample Mean: 12 Sample 3 Values: 8, 10 Sample Mean: 9 Sample 4 Values: 8, 11 Sample Mean:…

  • A) Null hypothesis: 70 Alternative hypothesis: 70 B-C)Test statistic: z=xˉ−μ0/σ/sqrt(n)=69.1−70/3.5/sqrt(49)=−1.8 Two-tailed p-value: p=2Φ(−∣z∣) ≈ 0.0719 Interpretation: There isn’t sufficient evidence that the mean breaking strength differs from 70; with these data we can’t conclude the machine is off spec. Decision (α = .05): p ≈ 0.0719 > .05 → Fail to reject H₀. D) z…

  • A1. Event A = row A = 10 + 20 = 30 P(A)=30/90=0.333 = 33.3% A2. Event B = column B = 10 + 20 = 30 P(B)=30/90=0.333 = 33.3% A3. We need P(A∪B) P(A∪B)=P(A)+P(B)−P(A∩B) : 30/90 + 30/90 -10/90 = 50/90 = .556 = 55.6% A4. P(A or B) = P(A) + P(B)? B1.…

Design a site like this with WordPress.com
Get started